what will be the thermal voltage at 300kelvin?

a)27mv b)300mv c)26mv d)1mv

Your Answer

c) 26mV
solution:
By shockley diode equation, 
        Vt=kT/q ;    Vt=thermal voltage,
                           k=Botlzmann constant= 8.617 * 10^-5 eV/K,
                           q= electric charge of electron
                             = 1.602*10^-19,
                           T=absolute temperature
      =>Vt=8.617*10^-5 * 300 / 1.602*10^-19
             =25.85mV

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