prove that: Angle OPQ = angle OPR . TRY for only math genius how to upload image suggest me
As the two right triangles ABR and APB are on the same side of AB and which is also the hypotenuse of both , the circle drawn taking AB as diameter will pass through R and P. So ABPR is a cyclic quadrilateral. Hence ∠ RPC =∠BAR Similarly ACPQ is also cyclic quadrilateral So ∠ BPQ =∠QAC But ∠BAR =∠QAC So ∠ RPC=∠ BPQ =>90- ∠ RPC=90-∠ BPQ => ∠ OPQ =∠OPR