Problems On Number
several ans given below....br /br /what about yr ans??????????????????
Answer is 4 .br /Here is the explanation :br /90 = 10 x 9br /Clearly, 653emxy/em is divisible by 10, so emy/em = 0br /Now, 653emx/em0 is divisible by 9.br /So, (6 + 5 + 3 + emx/em + 0) = (14 + emx/em) is divisible by 9. So, emx/em = 4.br /Hence, (emx/em + emy/em) = (4 + 0) = 4.
Consider 90=9*10.so,look at the divisible rule for 9 and 10.For 10,the last digit should be 0[y=0]. For 9,sum of all digits should be divisible by 9. 6+5+3+4+0=18....div by 9.so,x+y=4+0=4
strongAnswer:/strong Option strongC/strongbr /strongExplanation:/strongbr /90 = 10 x 9br /Clearly, 653emxy/em is divisible by 10, so emy/em = 0br /Now, 653emx/em0 is divisible by 9.br /So, (6 + 5 + 3 + emx/em + 0) = (14 + emx/em) is divisible by 9. So, emx/em = 4.br /Hence, (emx/em + emy/em) = (4 + 0) = 4.
It is divisible by 90 therfore it must have two numbers such as 9,10br /(x+y)=4
x+y=4 as divisibility by 90 needs multiple of both 9 and 10, which requires last term to be zero. for 9 sum of all terms should be divisible by 9. henceforth, x+y=4.
To get divisible by 9,the sum of digits of any given no. Should be divisible by 9.From this rule,it is clear that (x+y) = 4 ,,and here we have the divisor 90 so the last digit should be 0 and second last will be 4. Thats why the answer will be 4 & 0
4