11-1=10
11=10+1
multiply and divide r.h.s with 1-1
11= (10+1)(1-1) / (1-1)
11= (9+1+1)(1-1) / (1-1)
11= [9(1-1)+(1+1)(1-1)] / (1-1) ------->(a+b)(a-b)=a²-b²
11=9(1-1)/(1-1) + (1²-1²)/(1-1)
11=9 + (1-1)/(1-1)
11=9+1
do the same above process again, we get
11=8+1
this can be written as
11=9 => 11=10-1 => 10-1=11
add 19 and 5 on both sides in different equations, we get
29-1=30,
15-1=16
hence proved
11-1=10 11=10+1 multiply and divide r.h.s with 1-1 11= (10+1)(1-1) / (1-1) 11= (9+1+1)(1-1) / (1-1) 11= [9(1-1)+(1+1)(1-1)] / (1-1) ------->(a+b)(a-b)=a²-b² 11=9(1-1)/(1-1) + (1²-1²)/(1-1) 11=9 + (1-1)/(1-1) 11=9+1 do the same above process again, we get 11=8+1 this can be written as 11=9 => 11=10-1 => 10-1=11 add 19 and 5 on both sides in different equations, we get 29-1=30, 15-1=16 hence proved??
you can do like this...11-1=10, add 20 both sides, ie: 11+20-1=10+20, this will results 30=30; and in another one add 6 both sides,ie: 15+6-1=10+6, this will be 16=16. ok.
It's very simple question lifted by you Mr krishna....
Simply you may take "-" menus sign before substracting number as
29-1=30;
29-(-1)=30,
Similarly u can find out all given imputed through this way...
Hope you got my point exactly!