d/dx[tan(2x)]=sec²2x.d/dx(2x) Since d/dx(2x)=2 d/dx[tan(2x)]=2sec²(2x)
To differentiate tan 2x°, we'll use the chain rule of differentiation. The derivative of tan x is sec^2 x, and when we have a function within the tangent function, we apply the chain rule.br /So, differentiating tan 2x° with respect to x, we get:br /d/dx (tan 2x°) = sec^2(2x) * d/dx(2x)br /= sec^2(2x) * 2br /= 2sec^2(2x)br /br /In working through this mathematical problem, it's clear that precision and accuracy are key. For those seeking assistance or guidance with such calculations, I will suggest you to try strongmathsassignmenthelp.com/strong that can be incredibly valuable. Also, you can contact them at strong+1 (315) 557-6473/strong.
To differentiate tan(2x°) with respect to x, we can use the chain rule of differentiation. Recall that the derivative of tan(u) with respect to u is sec^2(u), and then we multiply by the derivative of the inside function (in this case, 2x°) with respect to x.br /br /So, the derivative of tan(2x°) with respect to x is:br /br /d(tan(2x°))/dx = sec^2(2x°) * d(2x°)/dxbr /br /Recall that the derivative of 2x° with respect to x is simply 2 times the derivative of x° with respect to x, which is 1.br /br /So, d(2x°)/dx = 2.br /br /Putting it all together:br /br /d(tan(2x°))/dx = sec^2(2x°) * 2br /br /Hence, the derivative of tan(2x°) with respect to x is 2sec^2(2x°).br /br /To have a concrete knowledge about trigonometry, you need to practice a lot more of such question. But sometimes we get stuck with such problems in our assignment. Thus, we need the help of some expert or tutors to solve thwm. In such type of situation, I would suggest you to visit a rel='nofollow' href="http://mathsassignmenthelp.com/?fbclid=IwAR26WDOIHlMOUoaFoysBz3NZI2xP6XNDb4ibq8afaQkERAqTRAzpfmh8L5o"mathsassignmenthelp.com/a for your assignment solution. You can also contact them at +1 (315) 557-6473.
please chech the attached link for detailed solution.br /a rel='nofollow' href="https://docs.google.com/document/d/1S1fG4mMzFzsGTg5uTCBTifQECI4cNNxUTqJb0r42yEw/edit?usp=sharing"https://docs.google.com/document/d/1S1fG4mMzFzsGTg5uTCBTifQECI4cNNxUTqJb0r42yEw/edit?usp=sharing/a
2x(degree)=[2*(22/7)*x]/180=(22x/630)br /tan2x(degree)=tan(22x/630)br /so the answer will be [(22/630][(sec2x)^2]br /br /
div style="box-sizing: border-box; color: rgb(102, 102, 102); font-family: Verdana, Arial, sans-serif; font-size: 14px; padding-left: 40px;"div style="box-sizing: border-box; min-height: 48px; word-break: break-all;"p style="box-sizing: border-box; margin: 0px 0px 10px; vertical-align: middle; min-height: 48px;"we substtitute 2x=u, we get y=tanu,u=2xbr style="box-sizing: border-box;" /dy/du=sec^2(u),du/dx=2br style="box-sizing: border-box;" /dy/dx=dy/du * du/dx (chain rule)br style="box-sizing: border-box;" /=sec^2(u) * 2/p/div/div
if we substtitute 2x=u, we get y=tanu,u=2xbr /dy/du=sec^2(u),du/dx=2br /dy/dx=dy/du * du/dx (chain rule)br /=sec^2(u) * 2br /=2sec^2(2x) (sub u=2x back in)
d/dx(tan2x) = sec^2(2x) d/dx(2x) = sec^2(2x) (2) = 2sec^2(2x)
To differentiate(taking with respect to x) this we can use chain rule:- d/dx(Tan2x)=2Sec²(2x)